KnotesFree Orthopaedic & FRCS notes, viva stations and higher order SBAs
Basic science / Biomechanics

Free body diagram

Basic scienceBiomechanicsthinKbox SBA

Free body diagram: A special type of vector diagram used to study the magnitude and direction of forces acting on body

Free Body Diagrams

A way of analysing the static forces and moments acting on a joint, FBD is a 2d simplification of a 3d structure

It is a static analysis (inertia – Newton’s first law)

All other variables must be equal to zero

6 variables are present

• Force in the x, y and z axes

• The moments created in these axes

Seven assumptions are made when using free body analysis

(JOIN BMW)

  1. Joints are frictionless hinges

  2. Only compressive forces act on joints

  3. Internal forces are equal - therefore not analysed (within the body)

  4. No antagonistic muscle action

  5. Bones are rigid rods

  6. Muscular force is in the direction of the muscle belly

  7. Weight of the body is concentrated at the centre of the body mass

Also remember

  • Body we draw should be in equilibrium

  • There are no antagonistic muscles

  • Muscle act only through tendon

  • JRF is always compressive

Hip FBD

6

Abductor moment = body moment in equilibrium

Fd = w x 5d

F = 5w

*w is generally taken as 5/6 of the body weight as the person is standing on one leg. Weight of one leg is generally taken a 1/6 body weight.

*F is the abductor force of contraction.

JRF

clipboard 3260763388

How to reduce JRF in hip?

Carry weight on same side!

8

F x d + F' x 2d = w x 5d

F + F' = 5w

F = 5w - F'

So the abductor force of contraction required is reduced from F to F-2F'

Carry stick on the opposite side!

9

Pressing the stick on to the ground will produce an equal and opposite ground reaction force, s.

F x d = w x 5d - s x 10d

F = 5w - 10s

So the abductor force of contraction required is reduced from F to F-10s

Ankle FBD

It is important to keep the ankle in dynamic equilibrium

10

This essentially make ankle a reverse hip joint, another type one lever

11

F x d = w x 3d

F = 3 w

JRF ankle

12

Spine FBD

Assume a man bending forward and trying to take a brick. Here the motion segment is again acting as a type 1 lever.

13

JRF Spine

14

Cervical Spine FBD

15

F x d = w x d

F = w

Patello femoral joint FBD

16

The quadriceps and patellar tendon are in equilibria, with a force 4F on either direction. The JRF is less than 4F. JRF is maximum when in flexion and negligible in extension of knee joint.

Knee joint FBD

17

We can see that when a person is about to raise from a chair, knee joint acts as a second order lever. Weight is acting down from the middle of the thigh and the quadriceps force F is directed towards the knee.

Shoulder joint FBD

18

Here we can see that shoulder is a third order lever.

Elbow and fingers FBD

19

Written/reviewed by Kishore Puthezhath

Professor of Orthopaedics and Consultant Paediatric Orthopaedic Surgeon

FRCS (Tr & Orth) revision resource

Reviewed: September 2026

Core revision references: Miller's Review of Orthopaedics; Campbell's Operative Orthopaedics; Orthobullets. Current specialty guidelines are linked within individual notes where applicable.